SOLUTION: Write y=2x^2+12x+14 in vertex form
Algebra
->
Quadratic-relations-and-conic-sections
-> SOLUTION: Write y=2x^2+12x+14 in vertex form
Log On
Algebra: Conic sections - ellipse, parabola, hyperbola
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Quadratic-relations-and-conic-sections
Question 112191
:
Write y=2x^2+12x+14 in vertex form
Answer by
jim_thompson5910(35256)
(
Show Source
):
You can
put this solution on YOUR website!
Start with the given quadratic
Subtract
from both sides
Factor out the leading coefficient
. This step is important since we want the
coefficient to be 1.
Take half of the x coefficient
to get
(ie
)
Now square
to get
(ie
)
Add this number (
) to the expression inside the parenthesis. Now the expression
is a perfect square trinomial.
Since we added
inside the parenthesis, we need to add
to the other side (remember, we factored out the leading coefficient
).
Factor
into
. Now the right side is a perfect square (note: if you need help with factoring, check out this
solver
)
Multiply
and
to get
.
Subtract 4 from both sides
Now the equation is in vertex form