SOLUTION: find the radius of a circle with center at (4,1), if a chord of length 4 square root of 2 is bisected at (7,4)

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Question 1086382: find the radius of a circle with center at (4,1), if a chord of length 4 square root of 2 is bisected at (7,4)
Answer by ikleyn(52848) About Me  (Show Source):
You can put this solution on YOUR website!
.
The triangle formed by the center of the circle, the midpoint of the chord and the endpoint of the chord is right-angled triangle.


One its leg is half length of the chord, i.e. %284%2Asqrt%282%29%29%2F2 = 2%2Asqrt%282%29.


The other leg length is the distance between the two given points, i.e.

sqrt%28%287-4%29%5E2%2B%284-1%29%5E2%29 = sqrt%289+%2B+9%29 = sqrt%2818%29.


Therefore, the radius R = sqrt%28%282%2Asqrt%282%29%29%5E2+%2B+18%29 = sqrt%288%2B18%29 = sqrt%2826%29.


Answer.  The radius of the circle R = sqrt%2826%29 units.