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Question 1045059: Acceleration of Gravity and Newton's Second Law
Newton's Second Law
"Change of motion is proportional to the force applied, and take place along the straight line the force acts."
Velocity and Distance Traveled by a Free Falling Object
The velocity after some time for a free falling object can be expressed as:
v = g t ------(1)
where
v = velocity (m/s)
The distance traveled after some time by a free falling object can be expressed as:
Why we are using HEIGHT=1/2 G(T^2)-----(2)
Here,
HEIGHT represents the height at which the object is falling.
G represents the gravitational force=9.8m/s^2
T represents the time taken for the object to fall.
My doubt is why we are using 1/2 in the equation--(2),why cant we use 1/4,3/4 or 1
Answer by ikleyn(52784)   (Show Source):
You can put this solution on YOUR website! .
Hey,
At this site we help students solving their math problems.
We assume that the students come to this site just having some preliminary knowledge.
It is not our task to educate the students from the zero level.
It is their teachers task and the task of their textbooks. And the students themselves.
Your level of knowledge is not enough to discuss these issues.
Therefore, my best advise is: take a textbook in Physics and learn from it.
Or learn from the Internet.
If you want to learn this subject.
And the last note is: G is not a gravitational force.
It is gravitational acceleration (sometimes called as "free fall acceleration").
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