SOLUTION: Consider the graph y=(x-k)^2 where k is any interger. What effect does changing the value of have on: The axis of symmetry The turning point The x and y intercepts The shape o

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Consider the graph y=(x-k)^2 where k is any interger. What effect does changing the value of have on: The axis of symmetry The turning point The x and y intercepts The shape o      Log On


   

Question 1031364: Consider the graph y=(x-k)^2 where k is any interger. What effect does changing the value of have on:
The axis of symmetry
The turning point
The x and y intercepts
The shape of the curve
You must present your findings for each specific value of k and generalise the the effects in the terms of K.
Thanks.
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Consider the graph y=(x-k)^2 where k is any integer. What effect does changing the value of have on: 

The red graph is for k=-6
The green graph is for k=-4
The dark blue graph is for k=-2
The wine-colored graph is for k=0
The green and yellow graph is for k=2
The light blue graph is for k=4
The purple graph is for k=6

The axis of symmetry
The axis of symmetry is always the vertical line through 
the turning point and its equation is x=k

The turning point
The turning point always the point (k,0)

The x and y intercepts
The x intercept is the vertex (k,0)
The y-intercept is the point (0,k2)

The shape of the curve
The curve always has the same shape 


Edwin