Tutors Answer Your Questions about Pythagorean-theorem (FREE)
Question 319509: In the following examples, calculate the gradient of the road using the rise/run formula.
(a)A person travels 10km along a road of incline 1km.
(b)A person travels 5km along a road of incline 2km.
(c)A road sign describes a hill on a road as 1 in 9.
(d)A road sign describes a steep hill on a road as 3 in 4.
(e)A man walks along a road for 4km with a slight incline of 1km.
Any help would be great. Thanks.
Click here to see answer by stanbon(75887)  |
Question 322352: Which of the following sets of 3 segments would make up the three sides of a right triangle?
I. 3 cm – 4 cm – 5 cm
II. 4 cm – 4 cm – 5 cm
III. 13 cm – 12 cm – 5cm
IV. 24 cm – 7 cm – 25 cm
a. I only
b. I and II only
c. I, II, and III only
d. I and IV only
e. I, III, and IV only
Click here to see answer by Fombitz(32388)  |
Question 324836: Can someone help me with this problem? It has 4 parts a,b,c and d. I have worked a,b and c this way: (d- I don't understand at all)
a) I have a right triangle and know one leg (8) and the hypotenuse (10), I have to find x. 10^ - 8^ = 100-64=36 root is 6 so x = 6. Is this correct?
b) Same triangle but I know the two legs 4a and 3a = 4^ + 3^ = 16+9=25, square root is 5 so x = 5. Correct?
c)I have a triangle with two sides of 13, a line bisects the triangle creating a right angle and the portion from the line coming down the middle to the corner of the triangle is 5 (whole triangle is 13,13,10). So I know a leg and a hypotenuse, right? 13^-5^= 169-25= 144 square root is 12 so x is 12?
d) now I have an equilateral triangle, line x bisects it creating a right angle and the bottom length is labeled "s". The line x would be a leg and half of s the other leg.... I am confused!! I have to find x but the only length I have is "s"
Any help would be appreciated!!
Click here to see answer by jim_thompson5910(35256) |
Question 324857: Another one I'm not sure of, if anyone can help?
A company wants to lay a string of buoys across a lake; to find the length, they made the following measurements:
It is a right triangle; one leg is 150ft and the hypotenuse is 180ft. Using the theorem I have 180-150=30 or 180^-150^=32,400 - 22,500 = 9900. I don't know if the solution is 9,900 ft or if there should be some conversions. 9900ft doesn't seem right to me if the other sides are only 180 and 150ft???
Click here to see answer by jim_thompson5910(35256) |
Question 326101: Using pythagoran theorem & using sine, here's the problem I'm stuck on.
side a= x, side b= unknown, side c = 3x in a right triangle, how do you find side b?
And then to find the sine of A & B of a right triangle. A is opposite side x and adjacent to unknown side. B is opposite unknown side and adjacent to side x. What are the angle measures of angle A and angle B?
Thanks for your help!
Click here to see answer by solver91311(24713)  |
Question 328700: A working student has to deliver a package to one of their clients.Before he can reach their client's office,he has to travel 3 km due east,then 3 km due south,and then 7 km due west.How far is their office from the clients office?
Click here to see answer by rapaljer(4671)  |
Question 330574: I have this Maths Question.
The sides of a rectangle are in the ratio 2:3
The diagonal is of length 26cm.
You have to find the perimeter of the rectangle.
I know that one side is two parts of the ratio and the other side is three parts of the ratio.
I have squared 26² To get 676.
Using Pythagoras theorem. The square of the sides with ratio 2: and 3: equal the longest side which is 26cm squared 676.
I tried taking the ratio’s dividing it 676 by 5, but this does not give the correct lengths for each side.
The answer for the whole perimeter is 20√13
From the answer I worked out from the ratio that the rectangle is made up of sides length 4√13, 6√13, 4√13, 6√13, adding these surds together gives you the answer 20√13.
4√13 = √16 * √13 = 208
6√13 = √36 * √13 = 468
208 + 468 = 676
What I can’t do is work out from the diagonal side 26cm squared to 676, how you then split the numbers into their correct ratio’s
I backward worked it out after looking at the answer but don’t know the procedure to do this.
Any help would be gratefully received.
Click here to see answer by nyc_function(2741)  |
Question 331770: Two sides of a right triangle are 8 and 10. Which of the following could be the
length of the third side?
I. 6
II. 15
III. 2 square root (41)
(A) I only (B) II only (C) I and II only (D) I and III only (E) I, II, and III
Click here to see answer by Earlsdon(6294) |
Question 331839: The equation h=-16^2 +112t gives the height (h) of an arrow shot upward from the ground with an initial velocity of 112ft/s, where t represents the time after the arrow leaves the ground. Using that equation, find the height of the arrow after (a)2seconds (b)5 seconds
Click here to see answer by Alan3354(69443)  |
|
Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420
|
