Tutors Answer Your Questions about Pythagorean-theorem (FREE)
Question 559794: A forty foot ladder is set against the wall. the distance of the base of the ladder to the wall is equal to the height of the ladder. How high is the ladder on the wall?
If I was to use the theorem, my answer is 0. (40)^2-(40)^2=b^2 1600-1600=b^2
0=b^2.
On the drawing it shows a 90o angle between the ladder and the wall.
Click here to see answer by mananth(16946)   |
Question 561713: The perimeter of a triangle is the "distance around the outside". If you have a triangle whose sides are a, b, and c, then the perimeter is a+b+c. Your peice of property is a triangle, which is bordered by three square peices of property. The first square (the hypotenuse) has and area of 200 square miles. The second square (side a) has an area of 50 square miles. The third square (side b) has an area of 72 square miles. What is the perimeter of your property?
(HINT: after you simplify your answer, it will be in the form a√b where a is a 2-digit number and b is a one-digit number.)
Please help me figure this out!
Click here to see answer by ankor@dixie-net.com(22740)  |
Question 562266: Y^2=x^2+12^2 represents the Pythagorean Theorem for a right triangle, where one of the shorter sides is 12 feet long, the other side is x(in feet), and y is the hypottenuse of the triangle.
Graph the equation using at least 5 to 8 points.
thank you
Rod Curley
Click here to see answer by ankor@dixie-net.com(22740) |
Question 562716: I've been stuck on this problem for a long time, and I REALLY need some help!
The question is:
"The longer leg of a right triangle is 4 feet longer than the other leg. Find the length of the two legs if the hypotenuse is 20 feet." I know that you set it up like this: x^2+(x+4)^2=20.
I need to show work, but I don't really know what I'm doing.
Click here to see answer by issacodegard(60)  |
Question 562913: I have a question. what do you do if you need to prove a triangle is a right triangle, but you only have variable coordinates for that triangle. Here's what I have so far: Triangle ABC: A(x,0); B(x,y); C(2x,0)
Finding AB: 
Finding BC: 
Finding AC: 
Final Steps: a^2+b^2=c^2
I'm confused on what to do next. I know that if a^2+b^2=c^2 then it is a right triangle. But, I can't solve it any furthur. I also can't use sin, cos, or tan. Thannk you in advance.
Click here to see answer by mananth(16946) |
Question 568107: It is my 2nd day in my geometry class, I have switched from an online school & I have an upcoming test on slope/midpoint/distance. Im stuck on a question from the study guide because I was not there for the lessons. I need help ASAP!
The question is:
The length of a rectangle is three times as long as it is wide. If the length of the diagonal is 10sqrt6 feet, find the area of the rectangle.
I cannot solve for this question no matter what I try!
Click here to see answer by scott8148(6628)  |
Question 572516: I am building a Triangular chicken coop.
A=4ft(tall)
B=4ft(wide)
D=5.66ft(hypotnuse)
of A the lower 2.5ft is going to be open while the remaining 1.5 ft will be enclosed making the lower "half" a right trapizoid and the top a right triangle
so if the trapizoid is
a=2.5ft tall
B=4ft wide
c=? (also width of upper right triangle)
d=? (hypotnuse)
1.5ft of A c and the remaining difference of D = the enclosed area
i just need to know what c & d are of the trapaziod that is the simpilest way i can put the question im doing this on my own and i have been out of school for just a year but im just stuck and dont remember how to do it i would very much appreciate your help Thank you.
Click here to see answer by Theo(13342)  |
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