Tutors Answer Your Questions about Pythagorean-theorem (FREE)
Question 453564: fire fighters just arrived at the Farquand building with a rescue truck. Mr.Farquand is stuck on a widow ledge 44feet directly above the top of the truck. The base of the ladder is a horizontal distance of 33 feet away from the building. Using the Pythagorean Theorem, determine how long the ladder must extend to reach Mr. Farquand.
Click here to see answer by Alan3354(69443)  |
Question 459618: in a parallelogram ABCD the diagonal AC is at right angle to AB if AB =12CM and BC =13 CM find the area of the parallelogram
given diagonal AC is at right angle to AB i.e.triangle ABC is a right angled triangle
now applying Pythagorean theorem
BC^2=AC^2+AB^2
given AB=12 cm and AC=13 cm
hence AC^2=BC^2-AB^2
AC^2=169-144=25
therefore AC=5 cm
now area of parallelogram ABCD=2*area of triangle ABC
since we know that area of right angle triangle=1/2 *base *altitude
so area of triangle ABC=1/2*12*5=30 sq cm
and hence area of parallelogram is 60 sq cm
Click here to see answer by pallavi(12) |
Question 460226: A toy manufacturer needs a piece of plastic in the shape of a right triangle with the longer leg 5 cm more than the shorter leg and the hypotenuse 10 cm more than the shorter leg. How long should the sides of the triangle be
Click here to see answer by checkley79(3341) |
Question 462086: in the left triangle, the hypotenuse has length 10, and the lower leg has length 8. in the right triangle, the hypotenuse has length 5, the longer leg has length 4, and the shorter leg has length 3. find the length, x, of the shorter leg of the left triangle
Click here to see answer by rwm(914) |
Question 464541: Hi, I need help in something simple actually, but somehow i just can't seem to find suitable solutions. My task is to look for real life applications of the Pythagorean Theorem. My teacher's definition of real life applications refers to things that happen daily, on the streets, etc. I need about 5 examples, but so far i've only managed to find 1. This is an example of what i've managed to find. I need about 3-4 more similar examples. Thank you in advance.
- Jolene
However, i can't seem to be able to paste the picture of the building here. I hope you'll be able to picture it.
-Suppose you want to design a building which is 50m high (in yellow) and 20m in width at the base (green).
Then the sloping wall (crucial in deciding the amount of material you will need, and pink in colour)
will be 53.85m (2 d.p).
Explanation:
Using Pythagoras’ Theorem:
502+202=Length of sloping wall2/Hypotenuse2
2900= Length of sloping wall2/Hypotenuse2
53.85m (2 d.p) =Length of sloping wall/Hypotenuse
Therefore, the sloping wall is 53.85m (2 d.p).
Click here to see answer by ewatrrr(24785)  |
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