Question 990594: ABCD is a rhombus of side 15cm. The diagonal AC is of length 20cm. Find the angle between AC and the side CD.
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! The diagonals are perpendicular to each other and bisect each other.
Therefore, the two legs of the right triangle are the sides of each diagonal and the side CD is the hypotenuse.
The angle is the adjacent side (10, half of the diagonal) divided by 15, the hypotenuse. That is the cosine, so cos of x=10/15
The arc cos of (10/15) is 48.2 degrees.
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