SOLUTION: The legs of a right isoceles triangle are each √71 feet. How long is the hypotenus of this triangle? Round your answer to the nearest whole number.

Algebra ->  Pythagorean-theorem -> SOLUTION: The legs of a right isoceles triangle are each √71 feet. How long is the hypotenus of this triangle? Round your answer to the nearest whole number.      Log On


   



Question 987535: The legs of a right isoceles triangle are each √71 feet. How long is the hypotenus of this triangle? Round your answer to the nearest whole number.
Found 2 solutions by josgarithmetic, jim_thompson5910:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The triangle described must have the right angle between the two equal sqrt%2871%29 sides.

h for hypotenuse;
h%5E2=%28sqrt%2871%29%29%5E2%2B%28sqrt%2871%29%29%5E2
h=sqrt%282%2A71%29 or h=sqrt%28142%29

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
a%5E2+%2B+b%5E2+=+c%5E2 Start with the pythagorean theorem


%28sqrt%2871%29%29%5E2+%2B+%28sqrt%2871%29%29%5E2+=+c%5E2 Plug in the given leg measurements


71+%2B+71+=+c%5E2 Square the square roots.


142+=+c%5E2


c%5E2=142


sqrt%28c%5E2%29=sqrt%28142%29 Apply the square root to both sides


c=sqrt%28142%29


c=11.916375287813 Use a calculator


c=12 Round to the nearest whole number


The hypotenuse is approximately 12 feet long