SOLUTION: 2. A rope is tied to the bow of a boat, 3 feet lower than a loop on a dock. The rope runs through the loop.
a. Find the distance from the boat to the dock as a function
Algebra ->
Pythagorean-theorem
-> SOLUTION: 2. A rope is tied to the bow of a boat, 3 feet lower than a loop on a dock. The rope runs through the loop.
a. Find the distance from the boat to the dock as a function
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Question 955591: 2. A rope is tied to the bow of a boat, 3 feet lower than a loop on a dock. The rope runs through the loop.
a. Find the distance from the boat to the dock as a function of the length of the rope from the loop to the boat.
I tried this
A^2 + B^2 =C^2
A^2 + 3^2 =C^2
A^2 =c^2 - 9
sqrt (A^2 ) = sqrt(C^2-9)
A = sqrt(C^2-9)
I don't know where to go from here! And what to do with (b.)
b. Now, if the length of rope is 10 – 2*t, find the position of the boat as a function of t. Answer by Edwin McCravy(20055) (Show Source):
You can put this solution on YOUR website! 2. A rope is tied to the bow of a boat, 3 feet lower than a loop on a dock. The rope runs through the loop.
a. Find the distance from the boat to the dock as a function of the length of the rope from the loop to the boat.
I tried this
A^2 + B^2 =C^2
A^2 + 3^2 =C^2
A^2 =c^2 - 9
sqrt (A^2 ) = sqrt(C^2-9)
A = sqrt(C^2-9)
I don't know where to go from here! And what to do with (b.)
b. Now, if the length of rope is 10 – 2*t, find the position of the boat as a function of t.
Draw the triangle so we will know what letter represents what:
We are letting the function be the distance A,
and the argument be the length of the rope C,
So you are right to have
Now we know that since the problem states that the length of the
rope is 10–2t, we know that we are to substitute 10-2t in place
of the length of the rope, which is C, and get
or we can do some algebra and get:
or even
Edwin
