SOLUTION: Hi, I need some help working out the value of x in the following equation: {{{ 25^2 = (2x)^2 + 2^2 }}}

Algebra ->  Pythagorean-theorem -> SOLUTION: Hi, I need some help working out the value of x in the following equation: {{{ 25^2 = (2x)^2 + 2^2 }}}      Log On


   

Question 953053: Hi, I need some help working out the value of x in the following equation:
+25%5E2+=+%282x%29%5E2+%2B+2%5E2+
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

+25%5E2+=+%282x%29%5E2+%2B+2%5E2+
+25%5E2+-2%5E2=+4x%5E2++
+625+-4=+4x%5E2++
+621=+4x%5E2++
+x%5E2+=621%2F4+
+x=sqrt%28621%2F4+%29++
+x=sqrt%289%2A69%29%2Fsqrt%284+%29++
+x=3sqrt%2869%29%2F2++......exact solution
+x=%283%2A8.306623862918075%29%2F2+++
+x=%2824.91987158875422%29%2F2+++
+x=12.45993579437711++
+x=12.46+........approximate solution