SOLUTION: (y+5)^2 + b^2 = 3y^2

Algebra ->  Pythagorean-theorem -> SOLUTION: (y+5)^2 + b^2 = 3y^2      Log On


   



Question 918645: (y+5)^2 + b^2 = 3y^2
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
%28y%2B5%29%5E2+%2B+b%5E2+=+3y%5E2%7D%7D%0D%0A%7B%7B%7By%5E2%2B10y%2B25%2Bb%5E2=3y%5E2
2y%5E2-10y-%2825%2Bb%29=0
Use the quadratic formula,
y=%2810+%2B-+%28sqrt%28100%2B8%2825%2Bb%29%29%29%29%2F2%282%29
Since it need to be positive, only the positive solution will be allowed.
y=%2810+%2B+sqrt%28100%2B200%2B8b%29%29%2F4
y=%2810%2Bsqrt%28300%2B8b%29%29%2F4