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The Hypotenuse of a right triangle is 9 meters long. Ones leg is 3 meters longer than the other. Find the lengths of the legs. Round the answer to the nearest tenth
Let the length of the smaller side be = x
the length of the othr side will be = x+3
the length of the hypotenuse is = 9 mts therefore formula is
(hypotenuse)^2 = (smaller side)^2 + (other side)^2
9^2 = x^2+(x+3)^2 ; 81 = x^2+x^2+6x+9 ; 81 = 2x^2+6x+9
2x^2+6x+9-81 = 0, 2x^2+6x-72=0 , x^2+3x-36=0 (divide by 2 throughout)
by using the formula
we get x = -3 +- sqrt 153/2
length of the smaller side = -3+-sqrt153/2 other side = 3+(-3+-sqrt153/2)
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