SOLUTION: If i know that the lentgh of the hypotenuse is 10cm and area of right triangle is 24 cm^2
How do i calculate the other two sides?
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-> SOLUTION: If i know that the lentgh of the hypotenuse is 10cm and area of right triangle is 24 cm^2
How do i calculate the other two sides?
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Question 829508: If i know that the lentgh of the hypotenuse is 10cm and area of right triangle is 24 cm^2
How do i calculate the other two sides? Found 2 solutions by oscargut, josgarithmetic:Answer by oscargut(2103) (Show Source):
You can put this solution on YOUR website! Let b and h the length of the 2 sides
24 = bh/2
and b^2+h^2= 100
If you solve it the lengths are 6 and 8
If you need more help you can contact me at
mthman@gmail.com
Thanks
You can put this solution on YOUR website! You need more data.
So far you have some x and y and hypotenuse=10.
You can say , and this is two unknown variables and one equation.
You also have . Is this enough?
Working with the area, , .
Substitute into the other equation:
x^4-100x^2+48^2=0
Try a substitution for this quadratic form, like , and solve first for u.
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Directly use general solution of quadratic formula.
784=4*196=4*4*49=4*4*7*7
u = 36 or u=64
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Now go back to definition of u and find x. You want only the positive values.
x=sqrt(u), so or
.
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ANSWER: Side lengths or legs are 6 and 8.
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