SOLUTION: Using the Pythagorean Theorem, and having to leave my answer in simplest radical form, how might I do so with a triangle of unknown hypotenuse, a leg of 15, and a leg of the square

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Question 818996: Using the Pythagorean Theorem, and having to leave my answer in simplest radical form, how might I do so with a triangle of unknown hypotenuse, a leg of 15, and a leg of the square root of 145?
Any help is appreciated!
Found 2 solutions by josgarithmetic, ewatrrr:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
15%5E2%2B%28sqrt%28145%29%29%5E2=hypotnuse%5E2
For convenience, h = hypotenuse.

15%5E2%2B%28sqrt%2829%2A5%29%29%5E2=h%5E2
h=sqrt%2815%5E2%2B29%2A5%29
h=sqrt%283%2A5%2A3%2A5%2B5%2A29%29
h=sqrt%28225%2B145%29=sqrt%28370%29
Recognize the divisibility by 10 and 2 and 5, but that will not help in any simplifcation.

highlight%28h=sqrt%28370%29%29 or h=sqrt%282%2A5%2A37%29

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi

 right triangle of unknown hypotenuse green%28x%29, 

a leg of 15, and a leg of the square root of 145?

Using the Pythagorean Theorem

15%5E2+%2B+%28sqrt%28145%29%29%5E2=+x%5E2

  225 + 145 = x^2  

     x^2 = 370

     x = sqrt%28370%29+ Simplest Radical Form