SOLUTION: If given a right triangle with the shorter leg being x and the longer leg being (2 times larger), so 2x. Find the hypotenuse in terms of the shorter leg (x).

Algebra ->  Pythagorean-theorem -> SOLUTION: If given a right triangle with the shorter leg being x and the longer leg being (2 times larger), so 2x. Find the hypotenuse in terms of the shorter leg (x).       Log On


   

Question 661000: If given a right triangle with the shorter leg being x and the longer leg being (2 times larger), so 2x. Find the hypotenuse in terms of the shorter leg (x).
Answer by colliefan(242) About Me  (Show Source):
You can put this solution on YOUR website!
If the legs are x and 2x, by the Pythagorean theorem:
x^2 + (2x)^2 = c^2 where c is the length of the hypotenuse.
x%5E2%2B4x%5E2=c%5E2
5x%5E2+=+c%5E2
sqrt%285x%5E2%29+=+sqrt%28c%5E2%29
sqrt%285%29%2Ax+=+c