SOLUTION: (x)^2+(1)^1=(x)^2

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Question 65195: (x)^2+(1)^1=(x)^2
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
(x)^2+(1)^1=(x)^2
This one has no solution, are you sure you copied it right?
x%5E2%2B1%5E2=x%5E2
x%5E2%2B1=x%5E2
x%5E2-x%5E2%2B1=x%5E2-x%5E2
0%2B1=0
1=0 Not true, your variables were eliminated, so there is no solution.
:
Since this was listed under pythagorean theorem, it's possible that you were just supposed to determine if the triangle was a right triangle. If you set this up right, it's not.
Another possibility is that you have your hypotenuse on the wrog side of the = sign. a%5E2%2Bb%5E2=c%5E2, it doesn't matter which legs you pick for a and b, but you have to pick the hypotenuse for c. The hypotenuse is the side opposite the right angle that is usually signalled with a box in the corner. If c=1, this is solvable:
x%5E2%2Bx%5E2=1%5E2
2x%5E2=1
2x%5E2%2F2=1%2F2
x=%2B-sqrt%281%2F2%29 You can ignore the negative value in this case because you can't have a negative side of a triangle.
x=sqrt%281%2F2%29
x=sqrt%281%2A2%2F%282%2A2%29%29
x=sqrt%282%2F4%29
x=sqrt%282%29%2Fsqrt%284%29
x=sqrt%282%29%2F2
Happy Calculating!!!