SOLUTION: (x-6)^2+(x)^2=30^2

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Question 65192: (x-6)^2+(x)^2=30^2
Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
(x-6)^2+(x)^2=30^2
x%5E2-12x%2B36%2Bx%5E2=900
2x%5E2-12x%2B36=900
2x%5E2-12x%2B36-900=900-900
2x%5E2-12x-864=0
2%28x%5E2-6x-432%29=0
2%28x%5E2-6x-432%29%2F2=0%2F2
x%5E2-6x-432=0
%28x-24%29%28x%2B18%29=0
x-24=0 or x+18=0
x-24+24=0+24 or x+18-18=0-18
x=24 or x=-18
You listed this under "pythagorean theorem." If this is a problem about the sides of a triangle, then use x=24 because you can't have a negative length of a triangle.
Happy Calculating!!!