SOLUTION: One leg of a right triangle is 7cm shorter than the other leg. It's area is 30cm^2. Find its perimeter.

Algebra ->  Pythagorean-theorem -> SOLUTION: One leg of a right triangle is 7cm shorter than the other leg. It's area is 30cm^2. Find its perimeter.      Log On


   



Question 636302: One leg of a right triangle is 7cm shorter than the other leg. It's area is 30cm^2. Find its perimeter.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Note: A%5BT%5D+=+%281%2F2%29b%2Ah
One leghighlight%28y%29 of a right triangle is 7cm shorter than the other leghighlight%28x%29.
Question states*** area is 30cm^2
30cm%5E2+=+%281%2F2%29x%2Ay || +y+=+%28x-7%29
60 = x(x - 7)
x^2 - 7x - 60 = 0
(x - 12)(x + 5) = 0 || Tossing out negative solution for unit measure
x = 12cm and y = 5cm
Applying the Pythagorean Theorem: sqrt%2812%5E2+%2B+5%5E2%29+=+13cm
P = 12cm + 5cm + 13cm = 30cm