SOLUTION: A ball is projected off of a 400-ft tall building at a velocity of 45 ft/sec. The function
f(x)= -16x^2+45x+400
(where x is the number of seconds elapsed) models
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-> SOLUTION: A ball is projected off of a 400-ft tall building at a velocity of 45 ft/sec. The function
f(x)= -16x^2+45x+400
(where x is the number of seconds elapsed) models
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Question 632454: A ball is projected off of a 400-ft tall building at a velocity of 45 ft/sec. The function
f(x)= -16x^2+45x+400
(where x is the number of seconds elapsed) models the height of the ball after the toss. The maximum height that the ball reaches is 431.6 ft. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! A ball is projected off of a 400-ft tall building at a velocity of 45 ft/sec. The function
f(x)= -16x^2+45x+400
(where x is the number of seconds elapsed) models the height of the ball after the toss. The maximum height that the ball reaches is 431.6 ft.
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