SOLUTION: A smaller commuter airline flies to three cities whose locations form a vertices of a right triangle. The total flight distance( from city A to city B to city C and back to city A)
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Question 586647: A smaller commuter airline flies to three cities whose locations form a vertices of a right triangle. The total flight distance( from city A to city B to city C and back to city A) is 1400 miles. It is 600 miles between the two cities that are furthest apart. Find the other two distances between cities..... Found 2 solutions by zoomkaboom4, Alan3354:Answer by zoomkaboom4(62) (Show Source):
You can put this solution on YOUR website! Since it is a right triangle, the other two cities are 400 miles apart because..
400+400+600 = 1400 miles.
You can put this solution on YOUR website! A smaller commuter airline flies to three cities whose locations form a vertices of a right triangle. The total flight distance( from city A to city B to city C and back to city A) is 1400 miles. It is 600 miles between the two cities that are furthest apart. Find the other two distances between cities
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The hypotenuse = 600 miles
The other 2 legs, a & b, add to 800 miles
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a + b = 800
b = 800 - a
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