SOLUTION: PLEASE HELP ME WITH THIS PROBLEM: Let f(x)=x^3-8x^2+17x-9. Use the factor theorem to find other solutions to f(x)-f(1)=0, besides x=1.

Algebra ->  Pythagorean-theorem -> SOLUTION: PLEASE HELP ME WITH THIS PROBLEM: Let f(x)=x^3-8x^2+17x-9. Use the factor theorem to find other solutions to f(x)-f(1)=0, besides x=1.      Log On


   

Question 54413This question is from textbook TRIGONOMETRY
: PLEASE HELP ME WITH THIS PROBLEM:
Let f(x)=x^3-8x^2+17x-9. Use the factor theorem to find other solutions to f(x)-f(1)=0, besides x=1. This question is from textbook TRIGONOMETRY

Found 2 solutions by Nate, stanbon:
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
f(x) = x^3 - 8x^2 + 17x - 9
f(1) = 1 - 8 + 17 - 9 = -7 + 8 = 1
f(x) - f(1) = 0
x^3 - 8x^2 + 17x - 9 - 1 = 0
x^3 - 8x^2 + 17x - 10 = 0
(x - 1)(x^2 - 7x + 10) = 0 use Descarte's Rule of Signs and all that stuff
(x - 1)(x - 5)(x - 2) = 0
x = 1 and x = 5 and x = 2
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2Cx%5E3+-+8x%5E2+%2B+17x+-+10%29

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
1 is not a root of the polynomial you posted.
Cheers,
Stan H.