SOLUTION: The diagonal of a square has the length of 8 sqrt 2. Find the length of a side of the triangle.

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Question 53688: The diagonal of a square has the length of 8 sqrt 2. Find the length of a side of the triangle.
Found 2 solutions by stanbon, aaaaaaaa:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Draw the square and the diagonal.
Label the sides as "x" and the diagonal as 8sqrt2
EQUATION:
x^2 + x^2 = (8sqrt2)^2
2x^2 = 64(2)
x^2=64
x=8
Each side is 8
Cheers,
Stan H.

Answer by aaaaaaaa(138) About Me  (Show Source):
You can put this solution on YOUR website!
By the pythagorean theorem, about the sides of a right triangle:
a%5E2+%2B+b%5E2+=+c%5E2, where c is the hypotenuse.
If you ignore two sides of a square, the remaining two sides and the diagonal form a right triangle. Since both sides we consider are equal, and we know the length of the diagonal, let's modify our equation a bit:
2a%5E2+=+%288sqrt%282%29%29%5E2
Distribute the exponentiation and solve:
2a%5E2+=+8%5E2%2Asqrt%282%29%5E2
2a%5E2+=+128
a%5E2+=+64
a+=+-8 or a+=+8
Since the length of the side of an square has to be positive, the sides of the square measure 8.