SOLUTION: I need help with another problem. I am solving for b using a^2+b^2=c^2, where a=9, and c = square root of 17. When I worked through, I came up with b^2=-64. This doesnt seem rig

Algebra ->  Pythagorean-theorem -> SOLUTION: I need help with another problem. I am solving for b using a^2+b^2=c^2, where a=9, and c = square root of 17. When I worked through, I came up with b^2=-64. This doesnt seem rig      Log On


   

Question 43995: I need help with another problem. I am solving for b using a^2+b^2=c^2, where a=9, and c = square root of 17. When I worked through, I came up with
b^2=-64. This doesnt seem right.
Answer by adamchapman(301) About Me  (Show Source):
You can put this solution on YOUR website!
a%5E2%2Bb%5E2=c%5E2
9%5E2%2Bb%5E2=17
81%2Bb%5E2=17
b%5E2=-64
this is geometrically impossible, as the square root of -64 cannot exist.
I think you may have labelled the sides of the triangle incorrectly. Always call the known lengths "a" and "b". Try:
a=9
b=sqrt%2817%29
this should give c=sqrt%2888%29
I hope this helps.
P.S. I am trying to start my own mathematics homework help website. I would be extremely grateful if you would send me your feedback on my help to adam.chapman@student.manchester.ac.uk.