SOLUTION: Let h be the function defined by h(x)=x2(2 means squared)-1, where the domain is the set of real numbers. a. find h(2) b. find h(-2) c. if h(t) = 15 what ar the possible value

Algebra ->  Pythagorean-theorem -> SOLUTION: Let h be the function defined by h(x)=x2(2 means squared)-1, where the domain is the set of real numbers. a. find h(2) b. find h(-2) c. if h(t) = 15 what ar the possible value      Log On


   

Question 41863: Let h be the function defined by h(x)=x2(2 means squared)-1, where the domain is the set of real numbers.
a. find h(2)
b. find h(-2)
c. if h(t) = 15 what ar the possible values of t?
d. find h(7.32).
thanks,
Found 2 solutions by nik_consult, PaulAllen65270:
Answer by nik_consult(24) About Me  (Show Source):
You can put this solution on YOUR website!
h(x)=x2(2 means squared)-1
(a) h(2)= (2)^2-1
= 4-1
= 3
(b)h(-2)= (-2)^2-1
= 4-1
= 3
(c) h(t) = 15
x^2 -1 = 15
x^2 = 1+15
= 16
x = sqrt(16)
= + 4 @ -4
(d) h(7.32)= (7.32)^2-1
= 53.5824 - 1
= 52.5824

Answer by PaulAllen65270(19) About Me  (Show Source):
You can put this solution on YOUR website!
When you have a function such as h%28x%29=x%5E2-1 and the problem says find H(2) it means for you to substitute 2 in place of x and solve the equation it will give you what h will be.
h=%282%29%5E2-1
When it has h%28t%29=15 it wants you to set the whole equation equal to 15 and solve it so
h%28t%29=t%5E2-1
h%28t%29=15
15=t%5E2-1
Now you have all the information to finish doing the work on this problem enjoy