SOLUTION: How do you use the Pythagorean Theorem to find the distance between the pair of points A(0,0), B(6,8) ?

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Question 339394: How do you use the Pythagorean Theorem to find the distance between the pair of points A(0,0), B(6,8) ?
Found 2 solutions by Edwin McCravy, stanbon:
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
How do you use the Pythagorean Theorem to find the distance between the pair of points A(0,0), B(6,8) ?

We want to find the length of the red line below




Now we draw a (green) horizontal line segment with
one end at A(0,0) and the other end exactly below
and vertically lined up with B(6,8) (actually the
point C(6,0))  Then we draw a (green) vertical line
segment upward from there C(6,0) to the point B(6,8): 




Now we have a right triangle ABC, and we are ready to call on
"ol' 'Thag"

AB%5E2=AC%5E2%2BCB%5E2

We can see that AC=6 and that CB=8, so
upon substituting:

AB%5E2=6%5E2%2B8%5E2
AB%5E2=36%2B64
AB%5E2=100
AB=sqrt%28100%29
AB=10

So now we know that AB is 10 units long.

We could convince ourselves that that line really is 10 units
long by taking a compass, placing the sharp point at A(0,0) and
the pencil point at B(6,8), and swinging a big arc and we see
that it cuts both axes at 10.

 


FYI, notice that we could have drawn a right triangle this 
way and gotten the same results:



Edwin

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How do you use the Pythagorean Theorem to find the distance between the pair of points A(0,0), B(6,8) ?
-------------
Plot the points.
Connect A and B. That is the distance you want.
Draw a vertical line from (6,8) down to the horizontal axis at (6,0)
Do you see the right triangle you have formed?
-------------------
Pythagoras says:
d^2 = (change in x)^2 + (change in y)^2
-----
d^2 = (6-0)^2 + (8-0)^2
---
d = sqrt[36 + 64]
d = sqrt[100]
d = 10
==================
Cheers,
Stan H.