SOLUTION: The width of a rectangle is 4 cm less than its length. If the area of the rectangle is 87cm^2 what are the dimensions of the rectangle? Round to the nearest thousandth.
I have
Algebra ->
Pythagorean-theorem
-> SOLUTION: The width of a rectangle is 4 cm less than its length. If the area of the rectangle is 87cm^2 what are the dimensions of the rectangle? Round to the nearest thousandth.
I have
Log On
Question 338556: The width of a rectangle is 4 cm less than its length. If the area of the rectangle is 87cm^2 what are the dimensions of the rectangle? Round to the nearest thousandth.
I have figured out the answer as
Length = 11.539
Width = 7.539
Just don't know the formula or how to solve, help would be greatly appreciated thank you. Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! The width of a rectangle is 4 cm less than its length. If the area of the rectangle is 87cm^2 what are the dimensions of the rectangle? Round to the nearest thousandth.
I have figured out the answer as
Length = 11.539
Width = 7.539
--------------------
Area = L*W
L = W+4
Area = (W+4)*W = 87
W^2 + 4W = 87
W^2 + 4W - 87 = 0