SOLUTION: your boat is traveling due north at 20 miles per hour. a friend's boat left at the same time and is traveling due west at 15 miles per hour. after an hour you get a call from your

Algebra ->  Pythagorean-theorem -> SOLUTION: your boat is traveling due north at 20 miles per hour. a friend's boat left at the same time and is traveling due west at 15 miles per hour. after an hour you get a call from your       Log On


   



Question 303246: your boat is traveling due north at 20 miles per hour. a friend's boat left at the same time and is traveling due west at 15 miles per hour. after an hour you get a call from your friend who tells you that he has just stopped because of engine trouble. how far must you travel to reach your friend?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
boat is traveling due north at 20 miles per hour.
a friend's boat left at the same time and is traveling due west at 15 miles per hour.
after an hour you get a call from your friend who tells you that he has just
stopped because of engine trouble. how far must you travel
:
this a right triangle problem, the distance between the boat is the hypotenuse
c^2 = a^2 + b^2
where
a = 20
b = 15
c = distance between the boats
:
c^2 = 20^2 + 15^2
c^2 = 400 + 225
c^2 = 625
c = sqrt%28625%29
c = 25 miles to travel to the friend