SOLUTION: 1) a=6 b=8 c=? 2) a=? b=12 c=13 3) a=? b=4 c=5 4) 9 21 ? 5) 24 10 ? 6) ? 3 4

Algebra ->  Pythagorean-theorem -> SOLUTION: 1) a=6 b=8 c=? 2) a=? b=12 c=13 3) a=? b=4 c=5 4) 9 21 ? 5) 24 10 ? 6) ? 3 4       Log On


   

Question 295329: 1) a=6 b=8 c=? 2) a=? b=12 c=13 3) a=? b=4 c=5 4) 9 21 ? 5) 24 10 ? 6) ? 3 4
Found 2 solutions by Edwin McCravy, richwmiller:
Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!

Next time you post, be sure to post the instructions.  
I will assume the instructions are this:

In the following, the first two numbers or question marks represent
the legs of a right triangle and the third number or question mark
represents the hypotenuse of that right triangle.  Give numbers
for all the question marks.


1) a=6 b=8 c=? 

c%5E2=a%5E2%2Bb%5E2
c%5E2=6%5E2%2B8%5E2
c%5E2=36%2B64
c%5E2=100
c=sqrt%28100%29
c=10

2) a=? b=12 c=13 

c%5E2=a%5E2%2Bb%5E2
13%5E2=a%5E2%2B12%5E2
169=a%5E2%2B144
25=a%5E2
a%5E2=25
a=sqrt%2825%29
a=5


3) a=? b=4 c=5 

c%5E2=a%5E2%2Bb%5E2
5%5E2=a%5E2%2B4%5E2
25=a%5E2%2B16
9=a%5E2
a%5E2=9
a=sqrt%289%29
a=3

4) 9 21 ? 

c%5E2=a%5E2%2Bb%5E2
c%5E2=9%5E2%2B21%5E2
c%5E2=81%2B441
c%5E2=522
c=sqrt%28522%29
c=sqrt%289%2A58%29
c=sqrt%289%29%2Asqrt%2858%29
c=3%2Asqrt%2858%29

5) 24 10 ?  

c%5E2=a%5E2%2Bb%5E2
c%5E2=24%5E2%2B10%5E2
c%5E2=576%2B100
c%5E2=676
c=sqrt%28676%29
c=26


6) ? 3 4

c%5E2=a%5E2%2Bb%5E2
4%5E2=a%5E2%2B3%5E2
16=a%5E2%2B9
7=a%5E2
a%5E2=7
a=sqrt%287%29

Edwin

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
1) 6,8, 10
multiple of the 3,4,5 right triangle.
2 5,12,13 another pythagorean triplet
3) the 3,4,5 again
5) 10 24 26
the 5,12,13 triangle again
So more than half of these you should know without having to calculate. Very important on a timed exam