SOLUTION: The base path of a baseball diamond forms a square. If it is 90 ft. from home to first, how far does the catcher have to throw to catch someone stealing second base? Give your an

Algebra ->  Pythagorean-theorem -> SOLUTION: The base path of a baseball diamond forms a square. If it is 90 ft. from home to first, how far does the catcher have to throw to catch someone stealing second base? Give your an      Log On


   



Question 292741: The base path of a baseball diamond forms a square. If it is 90 ft. from home to first, how far does the catcher have to throw to catch someone stealing second base?
Give your answer as a radical expresion in simplest form and then stimate the lenght to the nearest tenth of a foot.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
It is telling you that 90 ft is one
side of the square, and it is asking you
for the distance between opposite corners.
The sides are all equal to 90 ft
and, for a square, the diagonal and a side
are in the ratio sqrt%282%29 to 1,
so I can say sqrt%282%29%2F1+=+x%2F90
Multiply both sides by 90
90%2Asqrt%282%29+=+x
x+=+1.414%2A90
x+=+127.3 ft (rounded to nearest 1/10 th)