You can put this solution on YOUR website! How do i find the area of a 45°-45°-90° triangle with a 4-cm hypotenuse
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45-45l means the two legs are equal in length; let their length be "x":
Equation:
x^2 + x^2 = 4^2
2x^2 = 16
x^2 = 8
x = 2sqrt(2)
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Area = (1/2)(leg)(leg)
Area = (1/2)(8)
Area = 4 sqrt cm
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Cheers,
Stan H.