SOLUTION: Pythagorean triplets represent a special relation that both satisfy the Pythagorean theorem and as well as another characteristic. It is this additional characteristic that I am es

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Question 275017: Pythagorean triplets represent a special relation that both satisfy the Pythagorean theorem and as well as another characteristic. It is this additional characteristic that I am especially looking for. There are several formulas that will produce Pythagorean triplets. I need to find at least one. I need at least 5 other examples of triplets, not including 3-4-5.


Found 2 solutions by Edwin McCravy, Alan3354:
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!
Pythagorean triplets represent a special relation that both satisfy the Pythagorean theorem and as well as another characteristic. It is this additional characteristic that I am especially looking for. There are several formulas that will produce Pythagorean triplets. I need to find at least one. I need at least 5 other examples of triplets, not including 3-4-5.


One formula is

system%28a+=+k%28k%2B2q%29%2Cb+=+2q%28k%2Bq%29%2Cc+=+k%5E2%2B2qk%2B2q%5E2%29

where you can substitute any positive integers for q and k.
 
if k = 1 and q = 1 then we have a = 3, b = 4; and c = 5
if k = 1 and q = 2 then we have a = 5, b = 12; and c = 13
if k = 1 and q = 3 then we have a = 7, b = 24; and c = 25
if k = 1 and q = 4 then we have a = 9, b = 40; and c = 41
if k = 1 and q = 5 then we have a = 11, b = 60; and c = 61
if k = 1 and q = 6 then we have a = 13, b = 84; and c = 85
if k = 1 and q = 7 then we have a = 15, b = 112; and c = 113
if k = 1 and q = 8 then we have a = 17, b = 144; and c = 145
if k = 1 and q = 9 then we have a = 19, b = 180; and c = 181
if k = 1 and q = 10 then we have a = 21, b = 220; and c = 221
if k = 2 and q = 1 then we have a = 8, b = 6; and c = 10
if k = 2 and q = 2 then we have a = 12, b = 16; and c = 20
if k = 2 and q = 3 then we have a = 16, b = 30; and c = 34
if k = 2 and q = 4 then we have a = 20, b = 48; and c = 52
if k = 2 and q = 5 then we have a = 24, b = 70; and c = 74
if k = 2 and q = 6 then we have a = 28, b = 96; and c = 100
if k = 2 and q = 7 then we have a = 32, b = 126; and c = 130
if k = 2 and q = 8 then we have a = 36, b = 160; and c = 164
if k = 2 and q = 9 then we have a = 40, b = 198; and c = 202
if k = 2 and q = 10 then we have a = 44, b = 240; and c = 244
if k = 3 and q = 1 then we have a = 15, b = 8; and c = 17
if k = 3 and q = 2 then we have a = 21, b = 20; and c = 29
if k = 3 and q = 3 then we have a = 27, b = 36; and c = 45
if k = 3 and q = 4 then we have a = 33, b = 56; and c = 65
if k = 3 and q = 5 then we have a = 39, b = 80; and c = 89
if k = 3 and q = 6 then we have a = 45, b = 108; and c = 117
if k = 3 and q = 7 then we have a = 51, b = 140; and c = 149
if k = 3 and q = 8 then we have a = 57, b = 176; and c = 185
if k = 3 and q = 9 then we have a = 63, b = 216; and c = 225
if k = 3 and q = 10 then we have a = 69, b = 260; and c = 269
if k = 4 and q = 1 then we have a = 24, b = 10; and c = 26
if k = 4 and q = 2 then we have a = 32, b = 24; and c = 40
if k = 4 and q = 3 then we have a = 40, b = 42; and c = 58
if k = 4 and q = 4 then we have a = 48, b = 64; and c = 80
if k = 4 and q = 5 then we have a = 56, b = 90; and c = 106
if k = 4 and q = 6 then we have a = 64, b = 120; and c = 136
if k = 4 and q = 7 then we have a = 72, b = 154; and c = 170
if k = 4 and q = 8 then we have a = 80, b = 192; and c = 208
if k = 4 and q = 9 then we have a = 88, b = 234; and c = 250
if k = 4 and q = 10 then we have a = 96, b = 280; and c = 296
if k = 5 and q = 1 then we have a = 35, b = 12; and c = 37
if k = 5 and q = 2 then we have a = 45, b = 28; and c = 53
if k = 5 and q = 3 then we have a = 55, b = 48; and c = 73
if k = 5 and q = 4 then we have a = 65, b = 72; and c = 97
if k = 5 and q = 5 then we have a = 75, b = 100; and c = 125
if k = 5 and q = 6 then we have a = 85, b = 132; and c = 157
if k = 5 and q = 7 then we have a = 95, b = 168; and c = 193
if k = 5 and q = 8 then we have a = 105, b = 208; and c = 233
if k = 5 and q = 9 then we have a = 115, b = 252; and c = 277
if k = 5 and q = 10 then we have a = 125, b = 300; and c = 325
if k = 6 and q = 1 then we have a = 48, b = 14; and c = 50
if k = 6 and q = 2 then we have a = 60, b = 32; and c = 68
if k = 6 and q = 3 then we have a = 72, b = 54; and c = 90
if k = 6 and q = 4 then we have a = 84, b = 80; and c = 116
if k = 6 and q = 5 then we have a = 96, b = 110; and c = 146
if k = 6 and q = 6 then we have a = 108, b = 144; and c = 180
if k = 6 and q = 7 then we have a = 120, b = 182; and c = 218
if k = 6 and q = 8 then we have a = 132, b = 224; and c = 260
if k = 6 and q = 9 then we have a = 144, b = 270; and c = 306
if k = 6 and q = 10 then we have a = 156, b = 320; and c = 356
if k = 7 and q = 1 then we have a = 63, b = 16; and c = 65
if k = 7 and q = 2 then we have a = 77, b = 36; and c = 85
if k = 7 and q = 3 then we have a = 91, b = 60; and c = 109
if k = 7 and q = 4 then we have a = 105, b = 88; and c = 137
if k = 7 and q = 5 then we have a = 119, b = 120; and c = 169
if k = 7 and q = 6 then we have a = 133, b = 156; and c = 205
if k = 7 and q = 7 then we have a = 147, b = 196; and c = 245
if k = 7 and q = 8 then we have a = 161, b = 240; and c = 289
if k = 7 and q = 9 then we have a = 175, b = 288; and c = 337
if k = 7 and q = 10 then we have a = 189, b = 340; and c = 389
if k = 8 and q = 1 then we have a = 80, b = 18; and c = 82
if k = 8 and q = 2 then we have a = 96, b = 40; and c = 104
if k = 8 and q = 3 then we have a = 112, b = 66; and c = 130
if k = 8 and q = 4 then we have a = 128, b = 96; and c = 160
if k = 8 and q = 5 then we have a = 144, b = 130; and c = 194
if k = 8 and q = 6 then we have a = 160, b = 168; and c = 232
if k = 8 and q = 7 then we have a = 176, b = 210; and c = 274
if k = 8 and q = 8 then we have a = 192, b = 256; and c = 320
if k = 8 and q = 9 then we have a = 208, b = 306; and c = 370
if k = 8 and q = 10 then we have a = 224, b = 360; and c = 424
if k = 9 and q = 1 then we have a = 99, b = 20; and c = 101
if k = 9 and q = 2 then we have a = 117, b = 44; and c = 125
if k = 9 and q = 3 then we have a = 135, b = 72; and c = 153
if k = 9 and q = 4 then we have a = 153, b = 104; and c = 185
if k = 9 and q = 5 then we have a = 171, b = 140; and c = 221
if k = 9 and q = 6 then we have a = 189, b = 180; and c = 261
if k = 9 and q = 7 then we have a = 207, b = 224; and c = 305
if k = 9 and q = 8 then we have a = 225, b = 272; and c = 353
if k = 9 and q = 9 then we have a = 243, b = 324; and c = 405
if k = 9 and q = 10 then we have a = 261, b = 380; and c = 461
if k = 10 and q = 1 then we have a = 120, b = 22; and c = 122
if k = 10 and q = 2 then we have a = 140, b = 48; and c = 148
if k = 10 and q = 3 then we have a = 160, b = 78; and c = 178
if k = 10 and q = 4 then we have a = 180, b = 112; and c = 212
if k = 10 and q = 5 then we have a = 200, b = 150; and c = 250
if k = 10 and q = 6 then we have a = 220, b = 192; and c = 292
if k = 10 and q = 7 then we have a = 240, b = 238; and c = 338
if k = 10 and q = 8 then we have a = 260, b = 288; and c = 388
if k = 10 and q = 9 then we have a = 280, b = 342; and c = 442
if k = 10 and q = 10 then we have a = 300, b = 400; and c = 500

Edwin

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
In addition to the extensive list provided by the other tutor, it's interesting that
3%5E3+%2B+4%5E3+%2B+5%5E3+=+6%5E3
But, there are no instances of integers that fit
x%5En+%2B+y%5En+=+z%5En for any n <> 2
This was recently proven after centuries of effort - Fermat's Last Theorem.