SOLUTION: A rectangle has a width of 6 feet and a length of 8 feet. Find the length of the diagonal in feet.

Algebra ->  Pythagorean-theorem -> SOLUTION: A rectangle has a width of 6 feet and a length of 8 feet. Find the length of the diagonal in feet.      Log On


   



Question 270749: A rectangle has a width of 6 feet and a length of 8 feet. Find the length of the diagonal in feet.
Answer by Stitch(470) About Me  (Show Source):
You can put this solution on YOUR website!
Note that a rectangle is made up of 2 right triagles.
The Pythagorean theorem states that in any right triagle, A%5E2+%2B+B%5E2+=+C%5E2
Where C is the hypotenuse (or the diagonal)
A and B represent the sides of the triangle but it does not matter which one so We will set A = 6ft (the given width)
and B = 8ft (Given length)

Using: A%5E2+%2B+B%5E2+=+C%5E2
Your equation: 6%5E2+%2B+8%5E2+=+C%5E2
Simplify the equation
36+%2B+64+=+C%5E2
Combine like terms
100+=+C%5E2
Take the square root of both sides
highlight%28C+=+10%29
The diagonal of the retangle is 10ft