SOLUTION: I have a pythagorean problem. I understand that the solution is a^2+b^2=c^2, the problem is a=9,b=11 solve for c. so I got 9^2+11^2=81+121=202 however I have my answer of c^2=202,

Algebra ->  Pythagorean-theorem -> SOLUTION: I have a pythagorean problem. I understand that the solution is a^2+b^2=c^2, the problem is a=9,b=11 solve for c. so I got 9^2+11^2=81+121=202 however I have my answer of c^2=202,      Log On


   

Question 256384: I have a pythagorean problem. I understand that the solution is a^2+b^2=c^2, the problem is a=9,b=11 solve for c. so I got 9^2+11^2=81+121=202 however I have my answer of c^2=202, but can't figure out what c=? how do I find out what number is squared to get the answer?
Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
it's not an even number.

c^2 = 202

take square root of both sides of the equation to get:

c = +/- sqrt(202) = +/- 14.2126704

since c can't be negative, then it has to be:

c = 14.2126704

you need to use your calculator to get the square root of 202.