SOLUTION: The difference between the hypotenuse and the other two sides of a right triangle are respectively 8feet and 4 feet. the perimeter of the triangle is a) 48 b0 36 c) 50 d)

Algebra ->  Pythagorean-theorem -> SOLUTION: The difference between the hypotenuse and the other two sides of a right triangle are respectively 8feet and 4 feet. the perimeter of the triangle is a) 48 b0 36 c) 50 d)       Log On


   



Question 233396: The difference between the hypotenuse and the other two sides of a right triangle are respectively 8feet and 4 feet. the perimeter of the triangle is
a) 48 b0 36 c) 50 d) 37 e) none

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
The difference between the hypotenuse and the other two sides of a right triangle are respectively 8 feet and 4 feet. the perimeter of the triangle is

Shorter leg = a
Longer leg = b
Hypotenuse = c

Hypotenuse - shorter leg = 8, so

c+-+a+=+8

Hypotenuse - longer leg = 4, so

c+-+b+=+4

Since it is a right triangle, the Pythagorean theorem
holds, so

a%5E2%2Bb%5E2=c%5E2

So we have the system of three equations in three unknowns:

system%28c+-+a+=+8%2Cc+-+b+=+4%2Ca%5E2%2Bb%5E2=c%5E2%29

Solve the first one for a, and the second one for b:

a=c-8, b=c-4

Substitute in the third equation

a%5E2%2Bb%5E2=c%5E2
%28c-8%29%5E2%2B%28c-4%29%5E2=c%5E2

Can you solve that for c?  If not post again asking how.
It comes out as a factorable quadratic equation. 

You get two solutions for c, c=4, and c=20

We must discard the hypotenuse of 4, since it would be
impossible for c, the longest side to differ from the
longer leg by 8.

Therefore c=20

Substituting in  
a=c-8 and b=c-4

a=20-8 and b=20-4

or

a=12, b=16

So the perimeter = a%2Bb%2Bc=12%2B16%2B20=48, choice a).

Edwin