SOLUTION: Suppose you know the base of a rectangle has a length of 4 inches and a diagonal has a length of 5 inches. Find the area of the rectangle?
I'm clueless on this one. I just
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Pythagorean-theorem
-> SOLUTION: Suppose you know the base of a rectangle has a length of 4 inches and a diagonal has a length of 5 inches. Find the area of the rectangle?
I'm clueless on this one. I just
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Question 164371This question is from textbook Heart of Mathmatics
: Suppose you know the base of a rectangle has a length of 4 inches and a diagonal has a length of 5 inches. Find the area of the rectangle?
I'm clueless on this one. I just cant seem to get this. Any help would be greatly appreciated. This question is from textbook Heart of Mathmatics
You can put this solution on YOUR website! Because the "diagonal", "base" and "height" of the rectangle forms a "right triangle" we can apply Pythagorean's theorem.
.
Let h = height
then
h^2 + 4^2 = 5^2
h^2 + 16 = 25
h^2 = 9
h = 3 inches
.
Area is then:
"height" * "base"
= 3 * 4 = 12 square inches
