SOLUTION: Hypotenuse of right angle is 60 cm. if the leg is five cm longer than the other leg, what is lenght of the legs. I know the formula is c^2= a^2 + b^2 60^2= x^2 + (x+5)^2 60

Algebra ->  Pythagorean-theorem -> SOLUTION: Hypotenuse of right angle is 60 cm. if the leg is five cm longer than the other leg, what is lenght of the legs. I know the formula is c^2= a^2 + b^2 60^2= x^2 + (x+5)^2 60      Log On


   

Question 148741: Hypotenuse of right angle is 60 cm. if the leg is five cm longer than the other leg, what is lenght of the legs.
I know the formula is c^2= a^2 + b^2
60^2= x^2 + (x+5)^2
60^2= x^2 + x^2 +10x +25
3600= 2x^2 + 10x + 25
Now what are we solving 4 x?
Answer by oscargut(2103) About Me  (Show Source):
You can put this solution on YOUR website!
3600= 2x^2 + 10x + 25
then
2x^2+10x+25-3600=0
2x^2+10x-3575=0
x+=+%28-10+%2B-+sqrt%28+10%5E2-4%2A2%2A%28-3575%29+%29%29%2F%282%2A2%29+=
x+=+%28-10+%2B-+sqrt%28+28700+%29%29%2F%282%2A2%29+=
x+=+%28-10+%2B-+sqrt%28+28700+%29%29%2F%284%29+
then solutions are x+=+%28-10+%2B+sqrt%28+28700+%29%29%2F%284%29+ and x+=+%28-10+-+sqrt%28+28700+%29%29%2F%284%29+
positive solution is
x+=+%28-10+%2B+sqrt%28+28700+%29%29%2F%284%29+=39.85 (aprox)
So legs are 39.85 and 44.85 aprox