SOLUTION: I just want to make sure I have the right answer, if I don't could you please explain the steps to me. Problem---You are given a right triangle with the following lengths. Leg 1

Algebra ->  Pythagorean-theorem -> SOLUTION: I just want to make sure I have the right answer, if I don't could you please explain the steps to me. Problem---You are given a right triangle with the following lengths. Leg 1      Log On


   

Question 143529: I just want to make sure I have the right answer, if I don't could you please explain the steps to me.
Problem---You are given a right triangle with the following lengths. Leg 1 = 2, Leg 2 = x, Hypotenuse = 8. Use the Pythagorean Theorem to find x. Make sure you include an equation.
Here is my answer
c^2 - a^2 = b^2
8^2 - 2^2 =
sqrt64 - sqrt4 =
sqrt60 =
Sqrt4 X 15 =
2 sqrt15 = X
Answer is 2 sqrt15 = x
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
We basically have this triangle set up:


Since we can see that the triangle has legs of 2 and x with a hypotenuse of 8, we can use Pythagoreans theorem to find the unknown side.


Pythagoreans theorem:

a%5E2%2Bb%5E2=c%5E2 where a and b are the legs of the triangle and c is the hypotenuse



2%5E2%2Bx%5E2=8%5E2 Plug in a=2, b=x, and c=8. Now lets solve for x


4+%2B++x++%5E+2+=+6+4 Square each individual term



+x++%5E+2+=+6+4+-+4 Subtract 4 from both sides


+x++%5E+2+=+6+0 Combine like terms


s+q+r+t+%28++x++%5E+2+%29+=+s+q+r+t+%28+6+0+%29 Take the square root of both sides


x=2%2Asqrt%2815%29 Simplify the square root



So you are correct