SOLUTION: I cannot figure out the Pythagorean theorem when there is two variables and one regular number. I need to solve {{{x^2+3x^2=18^2}}}.I have(well I think) already between 5 2/3 and 5

Algebra ->  Pythagorean-theorem -> SOLUTION: I cannot figure out the Pythagorean theorem when there is two variables and one regular number. I need to solve {{{x^2+3x^2=18^2}}}.I have(well I think) already between 5 2/3 and 5      Log On


   

Question 123456This question is from textbook College Prepatory Mathematics 1
: I cannot figure out the Pythagorean theorem when there is two variables and one regular number. I need to solve x%5E2%2B3x%5E2=18%5E2.I have(well I think) already between 5 2/3 and 5.7. This question is from textbook College Prepatory Mathematics 1

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2B3x%5E2=18%5E2 Start with the given equation


x%5E2%2B3x%5E2=324 Square 18 to get 324


4x%5E2=324 Combine like terms


x%5E2=81 Divide both sides by 4


x=0%2B-sqrt%2881%29 Take the square root of both sides


So our answers are

x=9 or x=-9