SOLUTION: In the diagram, $ABCD$ is a square. Find $PR.$ [asy] unitsize(1.5 cm); pair A, B, C, D, P, R; A = (-1,1); B = (1,1); C = (1,-1); D = (-1,-1); P = (0,1) + dir(50); R

Algebra ->  Pythagorean-theorem -> SOLUTION: In the diagram, $ABCD$ is a square. Find $PR.$ [asy] unitsize(1.5 cm); pair A, B, C, D, P, R; A = (-1,1); B = (1,1); C = (1,-1); D = (-1,-1); P = (0,1) + dir(50); R       Log On


   



Question 1209579: In the diagram, $ABCD$ is a square. Find $PR.$
[asy]
unitsize(1.5 cm);
pair A, B, C, D, P, R;
A = (-1,1);
B = (1,1);
C = (1,-1);
D = (-1,-1);
P = (0,1) + dir(50);
R = -P;
draw(A--B--C--D--cycle);
draw(A--P--B);
draw(C--R--D);
label("$A$", A, W);
label("$B$", B, dir(0));
label("$C$", C, dir(0));
label("$D$", D, W);
label("$P$", P, N);
label("$R$", R, S);
label("$4$", (B + P)/2, NE, red);
label("$8$", (A + P)/2, NW, red);
label("$4 \sqrt{5}$", (A + B)/2, S, red);
label("$4$", (D + R)/2, SW, red);
label("$8$", (C + R)/2, SE, red);
label("$4 \sqrt{5}$", (C + D)/2, N, red);
[/asy]
AB=BC=CD=DA=4sqrt5
PA=CR=8
PB=RD=4

Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
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