SOLUTION: A force of 100N acting horizontally to the right is to be combined with another force P acting upward to the right at an angle of 15 degrees with the vertical. If the resultant for

Algebra ->  Pythagorean-theorem -> SOLUTION: A force of 100N acting horizontally to the right is to be combined with another force P acting upward to the right at an angle of 15 degrees with the vertical. If the resultant for      Log On


   



Question 1182677: A force of 100N acting horizontally to the right is to be combined with another force P acting upward to the right at an angle of 15 degrees with the vertical. If the resultant force of these two forces is 122.83N, solve force P.​

-> Is it possible to use phytagorean theorem? I'm having a hard time understanding the problem. Please help..

Found 3 solutions by robertb, ikleyn, Edwin McCravy:
Answer by robertb(5830) About Me  (Show Source):
You can put this solution on YOUR website!
UPDATE: I have edited the solution to correct the fact that cos(105) is a negative quantity, based on what solution other tutors have given.

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Use the cosine law, which says that,
where theta is the angle between vectors a and b, and vector c is the one opposite to theta.
Let abs%28c%29+=+122.83, abs%28a%29+=+100, and abs%28b%29+=+p, the magnitude of the resultant force.

===> 122.83%5E2+=+100%5E2+%2B+p%5E2+-+2%2Ap%2A100%2Acos%28105%5E0%29
<===> p%5E2+%2B+51.76380902p+-+5087.2089+=+0 after simplifying.
===>
Therefore the magnitude of force P is around 50N.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
A force of 100 N acting horizontally to the right is to be combined with another force P acting upward to the right
at an angle of 15 degrees with the vertical. If the resultant force of these two forces is 122.83N, solve force P.​
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Use the parallelogram rule of adding vectors and use the cosine law,  which says that

        ,

where  theta  is the angle between vectors  a  and  b,

and vector  c  is the sum of vectors   a  and  b.


In our case,   abs%28c%29+=+122.83,  abs%28a%29+=+100,  and  abs%28b%29+=+p,  the magnitude of the resultant force.

===>   122.83%5E2+=+100%5E2+%2B+p%5E2+-+2%2Ap%2A100%2Acos%28105%5E0%29

===>   p%5E2+%2B+51.76380902p+-+5087.2089+=+0   after simplifying.

===>   


Therefore, the magnitude of force P is around 50 newtons.             ANSWER

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Solved.



Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
Since it makes a 15o angle with the vertical, it makes a 75o angle with the
horizontal.





Yes, you can use the Pythagorean theorem.  I made a mistake somewhere, but
don't have time to find it and correct it. Maybe you can find the mistake.

      horizontal   |   vertical 
      components   |  components
---------------------------------
   |P|cos(75o) N   ||P|sin(75o) N
        100 N      |      0 N
---------------------------------
|P|(cos(75o)+100 N |  |P|sin(75o) N
               ______________________________________________________________ 
|Resultant| = √(sum of horizontal components)2 +(sum of vertical components)2



Square both sides

15079.85=%28abs%28P%29cos%2875%5Eo%29%2B100%29%5E2+%2B+%28abs%28P%29sin%2875%5Eo%29%29%5E2

15079.85=%28abs%28P%29cos%2875%5Eo%29%2B100%29%5E2+%2B+%28abs%28P%29sin%2875%5Eo%29%29%5E2





Subtract 10000 from both sides.







Since cos%5E2%28theta%29%2Bsin%5E2%28theta%29=1

5079.84=abs%28P%29%5E2%281%29%2B200cos%2875%5Eo%29abs%28P%29

5079.84=abs%28P%29%5E2%2B200cos%2875%5Eo%29abs%28P%29

0=abs%28P%29%5E2%2B200cos%2875%5Eo%29abs%28P%29-5079.84

0=abs%28P%29%5E2%2B51.76380902abs%28P%29-5079.84

Use the quadratic formula:



abs%28P%29+=+%28-51.76380902+%2B-+sqrt%282679.491924%2B20319.36%29%29%2F2+

abs%28P%29+=+%28-51.76380902+%2B-+sqrt%2822998.85192%29%29%2F2+

abs%28P%29+=+%28-51.76380902+%2B-+151.6537237%29%2F2+

We use the + since the - gives a negative value.

abs%28P%29+=+%28-51.76380902+%2B+151.6537237%29%2F2+

abs%28P%29+=+%28-51.76380902+%2B+151.6537237%29%2F2+

abs%28P%29+=+%2899.88991471%29%2F2+

abs%28P%29+=+49.94495735+N

That's the magnitude of the force P.

The angle it makes with the x-axis is found by

tan%28theta%29%22%22=%22%22matrix%281%2C2%2Cvertical%2Ccomponents%29%2Fmatrix%281%2C2%2Chorizontal%2Ccomponents%29

tan%28theta%29%22%22=%22%22%28abs%28P%29sin%2875%5Eo%29%29%2F%28abs%28P%29cos%2875%5Eo%29%5E%22%22%2B100%29

tan%28theta%29%22%22=%22%22%2849.94495735sin%2875%5Eo%29%29%2F%2849.94495735cos%2875%5Eo%29%5E%22%22%2B100%29

tan%28theta%29%22%22=%22%220.0769820774

theta%22%22=%22%224.402065933%5Eo

Edwin