You can put this solution on YOUR website! Thank you for the answer.. is there anyway you could walk me step by step through one of my problems so that I might be able to better understand? heres the first problem (how to find the hypotenuse)one side of the triangle is 5 base is 2 and hypotnuse is c. how do i solve this? this must also be solved and to the nearest 10th can you walk me through this? that would be really helpful. Thank you please reply as soon as possible.
5^2+2^2=C^2
25+4=C62
29=C^2
C=SQRT29
C=5.385 IS THE ANSWER.
TO ROUND TO THE NEAREST TENTHS (3) YOU LOOK AT THE DIGIT TO THE RIGHT OF THE 3.
IF IT IS 5 OR GREATER YOU NEED TO ADD A 1 TO THE 3 AND ZERO OUT ALL DIGITS TO THE RIGHT OF THE TENTH'S POSITION AFTER ADDING THE 1.
C=5.400
HOPE THIS HELPS.
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ASSUMING YOU HAVE A RIGHT TRIANGLE WITH SIDES=A & B & THE HYPOTENUSE IS C.
THEN: A^2+B^2=C^2
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LET A=5 & B=6 THEN WE HAVE:
5^2+6^2=C^2
25+36=C^2
61=C^2
C=SQRT61
C=7.8102496 ANSWER.
THIS ANSER TO THE NEAREST TENTH=7.8
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