SOLUTION: A wire is stretched from the ground to the top of an antenna tower. The wire is 30 feet long. The height of the tower is 6ft greater than the distance d from the towers base to th

Algebra ->  Pythagorean-theorem -> SOLUTION: A wire is stretched from the ground to the top of an antenna tower. The wire is 30 feet long. The height of the tower is 6ft greater than the distance d from the towers base to th      Log On


   

Question 1145157: A wire is stretched from the ground to the top of an antenna tower. The wire is 30 feet long. The height of the tower is 6ft greater than the distance d from the towers base to the end of the wire. Find the distance d and the height of the tower
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The wire, hypotenuse    30
Tower height            d+6
base to wire at ground  d

Solve this: d%5E2%2B%28d%2B6%29%5E2=30%5E2.

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

It is a (3,4,5) right angled triangle, with the hypotenuse of 30 ft (wire), vertical leg of 24 ft (tower height) 

and the horizontal leg of 18 ft (on the ground).


ANSWER.  The distance d is 18 ft.


CHECK.  24%5E2 + 18%5E2 = 576 + 324 = 900;  30%5E2 = 900.    ! Correct !