SOLUTION: Prove that (5,x,x+1)are Pythagorean triplets

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Question 1133609: Prove that (5,x,x+1)are Pythagorean triplets
Found 3 solutions by MathLover1, Alan3354, MathTherapy:
Answer by MathLover1(20849) About Me  (Show Source):
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(5,x,x%2B1) are Pythagorean triplets if
find x such that:
%28x%2B1%29%5E2=x%5E2%2B5%5E2
x%5E2+%2B+2+x+%2B+1+=+x%5E2+%2B+25
cross%28x%5E2%29+%2B+2+x+%2B+1+=+cross%28x%5E2%29+%2B+25
+2+x+%2B+1+=++25
+2+x+=++24
+x+=+12

(5,x,x%2B1)=(5,12,13)
13%5E2=12%5E2%2B5%5E2
169=144%2B25
169=169=> proof that (5,12,13) are Pythagorean triplets







Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Prove that (5,x,x+1)are Pythagorean triplets
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x = 2
5-2-3 is not a right triangle.
Disproven.
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If you meant to find x such that it's a right triangle, you should have said that.
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5^2 = 25
25/2 = 12.5 --> 12 & 13
5-12-13 is a right triangle.
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3-4-5 is also a solution.
3^2 = 9
9/2 = 4.5 --> 4 & 5
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In the same manner:
7^2 = 49
49/2 = 24.5 --> 7-24-25

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Prove that (5,x,x+1)are Pythagorean triplets
x CANNOT be the longest side (hypotenuse) since it's smaller than x + 1
Therefore, using x + 1 as hypotenuse, you'll get the following equation: matrix%281%2C3%2C+%28x+%2B+1%29%5E2%2C+%22=%22%2C+x%5E2+%2B+5%5E2%29, and the pythagorean triple: 5-12-13.
Using 5 as the hypotenuse, you'll get the following equation: matrix%281%2C3%2C+5%5E2%2C+%22=%22%2C+x%5E2+%2B+%28x+%2B+1%29%5E2%29, and the pythagorean triple: 3-4-5, when the POSITIVE (> 0) value of x is chosen.