Question 1127208: How do I find the Velocity of an object after it has fallen 20 feet Found 3 solutions by Boreal, MathLover1, Alan3354:Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! V=gt
time to fall a certain distance is s=(1/2)at^2
so 40=at^2
40=9.8 m/sec*t^2; t^2=4.08 sec, t=2.02 sec
Therefore, velocity is 9.8 m/sec^2*2.02 sec or 19.8 m/sec
Consider a body of mass m, acted on by a force F for time t. This produces an acceleration which we will designate with the letter g. The body has an initial velocity u, and after time t, it reaches a velocity v. It also travels a distance s.
where = initial velocity (= for a falling object) = acceleration due to gravity, ( for English units, or for SI units) = time, in =distance that body travels
Newton's equations of motion allow us to work out any of these parameters once we know three other parameters. So the three formulas are:
In terms of distance fallen,
where = distance fallen, ft.
Because and , therefore
Answer:
You can put this solution on YOUR website! Velocity is not the same as speed.
Velocity is a vector, includes speed and direction.
speed is a scalar, just a number.
