SOLUTION: Determine the length of an inclined plane whose measure is 10 meters longer than the rise and the run is 8 meters longer than the rise. So I’m trying to find the hypotenuse. c2=

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Question 1119154: Determine the length of an inclined plane whose measure is 10 meters longer than the rise and the run is 8 meters longer than the rise.
So I’m trying to find the hypotenuse.
c2= a2+b2
So ‘c’ will be the hypotenuse, ‘a’ and ‘b’ as opposite and adjacent.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Let x be the length of the hypotenuse (the length of the inclined plane).

That length is 10 more than the rise, so the length of the rise is x-10.

The run is 8 more than the rise, so the run is (x-10)+8 = x-2.

Then your equation c^2 = a^2+b^2 is

%28x-2%29%5E2%2B%28x-10%29%5E2+=+x%5E2

The problem should be easy to solve from there.

The equation is quadratic, so it will have two solutions. One of them yields a negative number for the length of the rise, so it can be ruled out.

Note that the answer is irrational; it is not a "nice" answer.