SOLUTION: A circle has its centre at (0,0) and passes through point (-6,8). Jill says the equation of the circle is x2+y2= 144 and the other end point if the diameter that passes through poi

Algebra ->  Pythagorean-theorem -> SOLUTION: A circle has its centre at (0,0) and passes through point (-6,8). Jill says the equation of the circle is x2+y2= 144 and the other end point if the diameter that passes through poi      Log On


   



Question 1114321: A circle has its centre at (0,0) and passes through point (-6,8). Jill says the equation of the circle is x2+y2= 144 and the other end point if the diameter that passes through point P is (6,8). Do you agree or disagree and why. What the equation should be
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
A circle has its centre at (0,0) and passes through point (-6,8).
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With the center at the Origin, r^2 = x^2 + y^2 = 100
--> x%5E2+%2B+y%5E2+=+100