SOLUTION: Kelly is mountain climbing with Jenny and has just climbed a 6-meter vertical rock face. Jenny is standing at the bottom of the cliff, looking up at Kelly. If Jenny is 9 meters awa

Algebra ->  Pythagorean-theorem -> SOLUTION: Kelly is mountain climbing with Jenny and has just climbed a 6-meter vertical rock face. Jenny is standing at the bottom of the cliff, looking up at Kelly. If Jenny is 9 meters awa      Log On


   

Question 1102091: Kelly is mountain climbing with Jenny and has just climbed a 6-meter vertical rock face. Jenny is standing at the bottom of the cliff, looking up at Kelly. If Jenny is 9 meters away from Kelly, how far away from the cliff is Jenny standing? If necessary, round to the nearest tenth.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The distance from Kelly to Jenny is
the hypotenuse, +c+, of a right triangle.
+c+=+9+ m
Let the height that Kelly has climbed = +a+
+a+=+6+ m
Let the distance from Jenny to the cliff = +b+
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Use the pythagorean theorem
+a%5E2+%2B+b%5E2+=+c%5E2+
+6%5E2+%2B+b%5E2+=+9%5E2+
+36+%2B+b%5E2+=+81+
+b%5E2+=+81+-+36+
+b%5E2+=+45+
+b+=+sqrt%28+45+%29+
+b+=+3%2Asqrt%28+5+%29+
+b+=+3%2A2.236+
+b+=+6.708+
Jenny is 6.708 m from the cliff
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check:
+a%5E2+%2B+b%5E2+=+c%5E2+
+36+%2B+6.708%5E2+=+81+
+36+%2B+45+=+81+
+81+=+81+
OK