SOLUTION: The hypotenuse of a right triangle is twice as long as one of the legs. If the other leg is the square root of 8, find the other leg. So I thought the problem would be set up as x^

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Question 1083771: The hypotenuse of a right triangle is twice as long as one of the legs. If the other leg is the square root of 8, find the other leg. So I thought the problem would be set up as x^2 + square root of eight squared = 2x squared. but the answer after I work the problem is not correct. Please help! My second day on this problem!
Found 2 solutions by Alan3354, MathLover1:
Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
The hypotenuse of a right triangle is twice as long as one of the legs. If the other leg is the square root of 8, find the other leg. So I thought the problem would be set up as x^2 + square root of eight squared = 2x squared. but the answer after I work the problem is not correct.
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1 side = sqrt(8)
Other side = a
c = 2a
---
c^2 = a^2 + 8
(2a)^2 = a^2 + 8
4a^2 = a^2 + 8
3a^2 = 8
a^2 = 8/3

Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website!

let the hypotenuse be ,legs and

in a right triangle:
if the hypotenuse of a right triangle isas long as one of the legs, let�s say , we have ->
if the other leg , than we have:

->->->->other leg

->

check:

.........round to one decimal place