An inscribed angle is measured by one-half its intercepted arc.
Inscribed angle ∠CAD and ∠DBC both subtend the same arc CD.
So ∠CAD = ∠DBC = 30°
That means ∠BAD = ∠BAC + ∠CAD = 50° + 30° = 80°
Since inscribed angle ∠BAD is measured by one-half its
intercepted arc, its intercepted arc BCD = 2(80°) = 160°.
arc BCD + arc BAD = 360°,
160° + arc BAD = 360°,
arc BAD = 200°
inscribed angle ∠BCD = 100° since it subtends arc BAD, and
has the measure of one-half its intercepted arc.
Edwin